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2 years ago

How many moles in 843.211 grams of c6h12o6?

1 answer:

3 0

Molar mass C6H12O6 = 12 x 6 + 1 x 12 + 16 x 6 = 180 g/mol

1 mole ------------ 180 g
( moles ) --------- 843.211 g

moles = 843.211 x 1 / 180

moles = 843.211 / 180

= 4,684 moles of C6H12O6

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mario62 [17]

I'm not sure but I think the answer is C or D.

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2 years ago

Read 2 more answers

1A: Consider these compounds:

Setler [38]

Solution :

Compound Ksp

$PbF_2$ $3.3 \times 10^{-8}$

$Ni(CN)_2$ $3 \times 10^{-23}$

FeS $8 \times 10^{-19}$

$CaSO_4$ $4.93 \times 10^{-5}$

$Mg(OH)_2$ $5.61 \times 10^{-12}$

Ksp of $$Ni(CN)_2$ and both compounds dissociate the same way. Hence $Mg(OH)_2$ is more soluble than $(B). \ Ni(CN)_2$

$Mg(OH)_2$ is less soluble than $(A). \ \ PbF_2 \ ()Ksp \ PbF_2 > Ksp \ \text{ of } \ Mg(OH)_2$

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$Ni(OH)_2$ can be directly compared with PbS, $AlPO_4, MnS$

$\text{For } \ Ni(OH)_2$

$AB_2(s) \rightarrow A^{2+} + 2B^{-}$

$Ni(OH)_2(s) \rightarrow Ni^{2+} + 2OH^-$

100

1-s s 2s

Ksp = $[A2+][B-]^2 = s \times (2s)^2 = 4s^3$

Hence they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.

For Silver Chloride

$AB(s) \rightarrow A^{x+}+B^{x-}$

$AgCl(s) \rightarrow Ag^+ + Cl^-$

1 0 0

1 - s s s

Ksp $=[A^{x+}][B^{x-}]=s \times s = s^2$

Hence, they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.

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2 years ago

In a tissue that metabolizes glucose via the pentose phosphate pathway, C-1 of glucose would be expected to end up principally i

Mnenie [13.5K]

Answer:

Carbon dioxide

Explanation:

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5 0

1 year ago

What’s number 1, 2, 3 <br> Major grade 6th grade

Maslowich

Answer:

1 is B

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Explanation:

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2 years ago

The solubility of magnesium phosphate at a given temperature is 0.173 g/L. Calculate the Ksp at this temperature. After you calc

jek_recluse [69]

Answer: $K_{sp}=1.25\times 10^{-14}$

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