Add 6 to both sides
2m2+7m+6=0
<h3>Answer:</h3>
Equation of the ellipse = 3x² + 5y² = 32
<h3>Step-by-step explanation:</h3>
<h2>Given:</h2>
- The centre of the ellipse is at the origin and the X axis is the major axis
- It passes through the points (-3, 1) and (2, -2)
<h2>To Find:</h2>
- The equation of the ellipse
<h2>Solution:</h2>
The equation of an ellipse is given by,
Given that the ellipse passes through the point (-3, 1)
Hence,
Cross multiplying we get,
- 9b² + a² = 1 ²× a²b²
- a²b² = 9b² + a²
Multiply by 4 on both sides,
- 4a²b² = 36b² + 4a²------(1)
Also by given the ellipse passes through the point (2, -2)
Substituting this,
Cross multiply,
- 4b² + 4a² = 1 × a²b²
- a²b² = 4b² + 4a²-------(2)
Subtracting equations 2 and 1,
- 3a²b² = 32b²
- 3a² = 32
- a² = 32/3----(3)
Substituting in 2,
- 32/3 × b² = 4b² + 4 × 32/3
- 32/3 b² = 4b² + 128/3
- 32/3 b² = (12b² + 128)/3
- 32b² = 12b² + 128
- 20b² = 128
- b² = 128/20 = 32/5
Substituting the values in the equation for ellipse,
Multiplying whole equation by 32 we get,
3x² + 5y² = 32
<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
Answer:
(4, -18)
Step-by-step explanation:
First Use this formula for the x -axis -b/2a
-8/2(1) is -4
Then plug in -4 to the equation
(-4)^2+8(-4)-2 = -18
<em>lol</em><em> </em><em>I'm</em><em> </em><em>i</em><em>n</em><em> </em><em>gra</em><em>de</em><em> </em><em>four</em><em> </em><em>,</em><em> sorry</em><em> </em><em>I </em><em>d</em><em>on't</em><em> know</em>
<span>(X^2+6)(4x-3)
</span><span>=<span><span>(<span><span>x2</span>+6</span>)</span><span>(<span><span>4x</span>+<span>−3</span></span>)</span></span></span><span>=<span><span><span><span><span>(<span>x2</span>)</span><span>(<span>4x</span>)</span></span>+<span><span>(<span>x2</span>)</span><span>(<span>−3</span>)</span></span></span>+<span><span>(6)</span><span>(<span>4x</span>)</span></span></span>+<span><span>(6)</span><span>(<span>−3</span><span>)
</span></span></span></span></span>4x3−3x2+24x−18 is the answer