Math question help me

Mathematics

1 answer:

lbvjy [14]2 years ago

3 0

Can’t see the picture can you post it again? Can only see 97^7/6b^3

You might be interested in

6. Which of the following is true about the

Gnom [1K]

C.
Y=mx + b is the formula (M being slope, and B being the y intercept) always start by going up or down by what the y-intercept number is, if it’s -9 you go down the y axis 9 numbers from the origin (0,0) and slope (m) is always better put in a fraction-5x is better put in -5/1x
Think of the top number of the fraction as ‘up/down’ and the bottom number as ‘over’ if the top number is negative you will go down from the y-intercept number that many times, the bottom number is how many spots you go over from that number , it is always to the right.

5 0

1 year ago

Over what interval is the function in this graph decreasing

posledela

C)

you look at were the graph starts to decrease then look at the X-VALUE not the y-value

the x-val at the start of the decrease is -3 and at the end of it it is 2 therefor -3 $\leq$ x $\leq$ 2

6 0

3 years ago

Read 2 more answers

Can you solve for y plz

vredina [299]

Solve the top equation for x and then substitute that into the bottom equation and solve for y:
Top equation: subtract 4 from both sides to get x = y - 4
Substitution and simplify:
y = 4(y - 4) - 10
y = 4y - 16 - 10
y = 4y - 26
-3y = -26
y = 26/3 or 8 1/3 or 8.333 (those are all the same but in different forms)

8 0

2 years ago

What coordinate changes when reflected over the y-axis?

Alexeev081 [22]

Answer:

When a point is reflected across the y-axis, the y-coordinate(s) remain the same. But the x-coordinate(s) is transformed into opposite signs.

7 0

2 years ago

Read 2 more answers

Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'

AleksandrR [38]

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.

</span> $\dfrac{9}{10} = x + \dfrac{3}{5}$

$x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}$

That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)

Let $a, b, c$ be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

$\pm a \pm b = \pm c$

Let's get rid of the plus/minuses. Squaring,

$a^2 + b^2\pm 2ab = c^2$

$\pm 2ab = c^2-a^2-b^2$

$4a^2b^2 = (c^2-a^2-b^2)^2$

For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}$

$c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0

3 years ago