Consider a function f(x), the linear approximation L(x) of f(x) is given by
Given the quantity:
We approximate the quantity using the function
, where x = 203.
We choose a = 200, thus the linear approximation is given as follows:
The number of companies is quite large. That is, n is quite large.
The probability that a company declares bankruptcy is quite small , p is quite small.
np = the mean number of bankruptcies = 2 = a finite number.
Hence we can apply Poisson distribution for the data.
P (x=5 | mean =2) = e-2 25/5! = e-2 * 32/120 = 0.036089
Alternatively
=poisson(5,2,0) = 0.036089
P(x≥ 5 | mean =2) = 1- P( x ≤ 4) = 1- e-2 (1+2+22/2!+23/3!+24/4!)= 1-e-2 (1+2+2+8/6+16/24)= 1-e-2(7)
=0.052653
Alternatively
= 1- poisson(4,2,1) =0.052653
P(X > 5 | mean =2) = 1- p(x
≤ 5) =1- e-2 (1+2+22/2!+23/3!+24/4!+25/5!)= 1-e-2(7+4/15)
=0.016564
alternatively=1-poisson(5,2,1)
=0.016564
First, you plug your given values in. Since x is 1.5, it will be multiples by 2x to get 3.2. Since y is -3, it will be added to 1 to get -2. Finally, the two are multiplied together to get -6.4 if I am correct.
Answer:
-(2x+1) ,6x-8x=-2x,+1-2=1
3h + 7 next time do it you self smh
