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2 years ago

How many mmHg are in 1.6320 atm

Chemistry

2 answers:

OverLord2011 [107]2 years ago

7 0

1240.319921657472 mmHg

Olegator [25]2 years ago

7 0

Answer: The correct answer is 1240.3198 mmHg.

Explanation:

We are given a value of pressure in atmosphere, which is 1.6320 atm.

To convert this value of pressure in mmHg, we need to use a conversion factor:

$1atm=760mmHg$

Converting the given value in mmHg, we get:

$1.6320atm=1.6320atm\times \frac{760mmHg}{1atm}\\\\\Rightarrow 1240.3198mmHg$

Hence, the correct answer is 1240.3198 mmHg.

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Ammonium Phosphate (NH4)3PO4 is a strong electrolyte. What will be the concentration of all the ions in a 0.9 M solution of ammo

katrin2010 [14]

There are 3 moles of

$NH_4^+$

per 1 mole of salt and 1 mole of

$PO_{4}^{3-}$

per mole of salt, the total ionic concentrations must be

$2.7 M$ of $NH_4^{+}$ , and $0.9 M$ of $PO_4^{3-}$

3 0

2 years ago

Can anybody check my answer?

anzhelika [568]

Answer:

$\boxed{\text{25. 20 L; 26. 49 K}}$

Explanation:

25. Boyle's Law

The temperature and amount of gas are constant, so we can use Boyle’s Law.

$p_{1}V_{1} = p_{2}V_{2}$

Data:

$\begin{array}{rcrrcl}p_{1}& =& \text{100 kPa}\qquad & V_{1} &= & \text{10.00 L} \\p_{2}& =& \text{50 kPa}\qquad & V_{2} &= & ?\\\end{array}$

Calculations:

$\begin{array}{rcl}100 \times 10.00 & =& 50V_{2}\\1000 & = & 50V_{2}\\V_{2} & = &\textbf{20 L}\\\end{array}\\\text{The new volume will be } \boxed{\textbf{20 L}}$

26. Ideal Gas Law

We have p, V and n, so we can use the Ideal Gas Law to calculate the volume.

pV = nRT

Data:

p = 101.3 kPa

V = 20 L

n = 5 mol

R = 8.314 kPa·L·K⁻¹mol⁻¹

Calculation:

101.3 × 20 = 5 × 8.314 × T

2026 = 41.57T

$T = \dfrac{2026}{41.57} = \textbf{49 K}\\\\\text{The Kelvin temperature is }\boxed{\textbf{49 K}}$

6 0

2 years ago

If an ideal gas has a pressure of 5.49 atm, a temperature of 88.78 °c, and has a volume of 22.03 l, how many moles of gas are in

kirza4 [7]

N = (PV)/RT
(T = 88.78 + 273 = 361.78K)
(R = 22.4/273 = 0.082)
= (5.49 x 22.03)/(0.082 x 361.78) = ?
Put it into the calculator. It's hard to do that on a mobile phone.

7 0

3 years ago

List 4 indicators that a chemical change has probably occurred

aivan3 [116]

1. Change in color
2. Formation of bubbles
3. Formation of a precipitate
4. Begins to make an odor

6 0

2 years ago

The 488 nm laser is shine on a lithium metal whose work function is 2.9 eV will you be able to see any photoelectrons? if yes wh

nalin [4]

Answer:

There will not be any ejection of photoelectrons

Explanation:

Energy of the photon= hc/λ

Where;

h= Plank's constant

c= speed of light

λ= wavelength of the incident photon

E= 6.6×10^-34 × 3 ×10^8/488 × 10^-9

E= 4.1 ×10^-19 J

Work function of the metal (Wo)= 2.9 eV × 1.6 × 10^-19 = 4.64 × 10^-19 J

There can only be ejected photoelectrons when E>Wo but in this case, E<Wo hence there will not be any ejection of photoelectrons.

3 0

2 years ago