Answer:
The answer is only 2 because even numbers are divisible by 2, also 2 is a prime number.
Answer:
f(-4a) = -16a + 8
Step-by-step explanation:
Substitute -4a into the equation
4x(-4a) + 8 = -16a +8
So 2 real solutions
just write 2 factors and expand
(x-3)(x-4)=0
x^2-7x+12=0
discriminant is when you have b^2-4ac
so subsitute
ax^2+bx+c=0
a=1
b=-7
c=12
-7^2-4(1)(12)
49-48=1
discriminant=1
one real solution would be
(x-1)(x-1)=0
x^2-2x+1=0
discriminant=-2^2-4(1)(1)=4-4=0
discriminant=0
no real solutions has the discriminant less than zero
let's say that b=1 and c=20 and a=1
basically, we need a set of numbers where b^2 is less than 4acso
1^2-4(1)(20)=1-80=-79
then we subsitute
x^2+x+20=0
Answer:
Step-by-step explanation:
We want to describe the solution set on the number line as an inequality.
We have open circles at both ends.
This means the inequalities are not the ones containing equal sign.
The number line started from -3 and ended at 13 non inclusive.
This means the solution set for the inequality are all real numbers greater than -3 but less than 13.
We write this as:
Answer:
12 km
Step-by-step explanation:
C is 5 km
4+3+5=12
pls brainliest