Answer:
Im pretty sure its 1. Not 100% sure but im 99.99% sure
Step-by-step explanation:
I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
Answer:
140 + 10 = 150, so 150 + 140 = 290 students. There are 140 + 10 = 150 students at Westside Middle School.
Step-by-step explanation:
Answer:31.4cm
Step-by-step explanation:
Circumference=2×π×(diameter/2)
Circumference=2×3.14×10/2
Circumference=(2×3.14×5)
Circumference=31.
Answer:
B. What was the highest temperature this month?
Step-by-step explanation:
Rory is recording the <em>high</em><em>est</em><em> temperature</em> for the duration of the day for month's worth of data.
B. is the easiest one to answer, as you simply will have to look for the greatest number within the set, and that will be the answer.
A. is too broad, and does not imply that only the "high temperature" is needed, rather just a leveled temperature within day in that month.
C. is the opposite of what Rory had recorded, and without data, he cannot answer it.
D. is answerable as well, but, again, the only temperature recorded is the high temperature. Temperature can fluctuate depending on the time of the day, and can be in the 50s one hour and the 90s in another.
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