Answer:
Explanation:
given,
In first case Volume remains constant.
Work done in the first case is zero.
In Second case Volume change
V₁ = 0.2 m³
V₂ = 0.11 m³
Pressure, P = 5.5 x 10⁵ Pa
Work done = Pressure x change in volume
W = P ΔV
Hence, Work done when volume changes is equal to
For the first part, we are looking for Vf when dy=11.0
Upward is positive, downward is negative.
So <span>Vf = square root [2(-9.8)(11.0) + (18.0)^2] </span>
<span>Vf = 10.4 m/s your answer is correct.
For the part b, t is equals to the time took to reach and dy is equals to 11.0
you did, </span>11= 18t m/s-(1/2) 9.8t^2 then <span>-11 + 18t- 9.8t^2. By quadratic formula, for the way down the answer is 2.9 s while on it's way up, the answer is 0.77 s</span><span>
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I think it’s ultraviolet, if not i’m sorry!