Answer: x^2 - 8x + 16
Let y = x-4
(x-4)^2 = (x-4)*(x-4)
(x-4)^2 = y*(x-4) ... replace one copy of (x-4) with y
(x-4)^2 = x*y - 4*y .... distribute
(x-4)^2 = x*( y ) - 4( y )
(x-4)^2 = x(x - 4) - 4(x - 4) ... replace y with x-4
(x-4)^2 = x^2-4x-4x+16 .... distribute
(x-4)^2 = x^2 - 8x + 16
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If you write it in decimal
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1580 ÷ 13 = 121.53
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If you write in fraction
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If you write in quotient and remainder
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1580 ÷ 13 = 121 Remainder 7
Answer:
y = -1/4x - 2
Step-by-step explanation:
I'm going to write this equation in slope intercept form, which looks like this: y = mx + b. First, write the equation using the slope given. It should look like this:
y = -1/4x + b
Next, you must find the y intercept by plugging in the point to the equation. This is what it looks like: 0 = -1/4(-8) + b. Multiply -1/4 by -8 to get 2. This is what your equation should look like now: 0 = 2 + b. Subtract 2 from both sides of the equation to get -2 = b. Go back to your original equation and plug -2 in for b. This is your final equation:
y = -1/4x - 2
Hope this helped!