Answer:
the balls are larger, or don't pack as tightly
Step-by-step explanation:
The volume by either measure will depend on a couple of factors:
- the volume of the unit used (ball or cube)
- the way the units can be packed
In a rectangular space, such as a box, it may be easier to pack cubes than balls. So, more cubes of the same volume would fit simply because they can be packed closer together.
We aren't told the volume of either the cube or the ball, and we're not told the extent to which the packing is optimized.
Fewer balls may fit because their packing is not as well optimized as that of the cubes, or because each has a larger volume than the cube being used.
Step-by-step explanation:
hey,u need help with what?
8,9,10,11,11,14,18,28,28,29,40,41,41,44,45,47,55 which histogram represents data
Elenna [48]
Answer:
did this b4
Step-by-step explanation:
I used bars of width 10. There are 3 values from 0-9; 4 values from 10-19; 3 values from 20-29; 0 values from 30-39; 6 values from 40-49; and 1 value from 50-59.
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Ms. Cassidy instructed Miguel to change one sign of the graph of y < 2x – 4 so that point (2, 3) can be included in the solution set.
To check which of the given options might Miguel write we check the inequality that holds true for the point (2,3).Substituting x=2 ,y=3 we have:
1) y < 2x – 1
3<2(2)-1
3<3 Not True.
2)y ≤ 2x – 4
3≤ 2(2) -4
3≤ 0 .Not true.
3) y > 2x – 4
3> 2(2)-4
3> 0 True.
4) y < 2x + 4
3<2(2)+4
3<8 True
5) .y < 3.5x – 4
3< 3.5(2)-4
3<3 Not true
6) y < 4x – 4
3<4(2)-4
3<4 True.
Options 3 ,4 ,6 holds true for the point (2,3)