A regular quadrilateral prism has 12 edges. It is given perimeter of the base 32 cm. Length of each edge of base will be 32÷4=8 cm. The 4 edges at the top will also have the same number of edges that is 4 with measure 8cm each.
Given: The height of the prism is 2 times greater than the length of the base edge.Height of prism = 2(8)= 16cm. Number of edges with measure 16 cm is 4.
Sum of all the 12 edges= 8+8+8+8+16+16+16+16+8+8+8+8=128 cm.
The answer is d i am sure
You must calculate h(24) first. h(x) = x^2 + 1, so h(24) = 577.
g(x) = 3x, so g(577) = 3(577) = 1731 (answer). We don't need f(x).
Composite because the factors that go into it ate 2 and 9, 1 and 18, 6 and 3
