A linear function can’t repeat but a quadratic function can
x = 20 - -5 = 20 + 5 = 25
y = 16 - 1 = 15
<h2>
x = 25</h2><h2>
y = 15</h2>
Answer:
x = 4
Explanation:
Given the expression;
![\sqrt[]{x}-4\text{ = -2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7Bx%7D-4%5Ctext%7B%20%3D%20-2%7D)
Add 4 to both sides
![\begin{gathered} \sqrt[]{x}-4+4\text{ = -2+4} \\ \sqrt[]{x}=\text{ 2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csqrt%5B%5D%7Bx%7D-4%2B4%5Ctext%7B%20%3D%20-2%2B4%7D%20%5C%5C%20%5Csqrt%5B%5D%7Bx%7D%3D%5Ctext%7B%202%7D%20%5Cend%7Bgathered%7D)
Square both sides
![\begin{gathered} (\sqrt[]{x})^2=2^2 \\ x\text{ = 4} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%28%5Csqrt%5B%5D%7Bx%7D%29%5E2%3D2%5E2%20%5C%5C%20x%5Ctext%7B%20%3D%204%7D%20%5Cend%7Bgathered%7D)
Hence the value of x is 4
Answer:
3.68 x 10^-1
Step-by-step explanation:
............
Answer:
C=10
Step-by-step explanation:
To solve this problem, first, you have to isolate it on one side of the equation. Remember, isolate c on one side of the equation.
3/2c+23-23=38-23 (subtract 23 from both sides.)
38-23 (solve.)
38-23=15
3/2c=15
2*3/2c=15*2 (multiply 2 from both sides.)
15*2 (solve.)
15*2=30
3c=30
3c/3=30/3 (divide by 3 from both sides.)
30/3 (solve.)
30/3=10
c=10
