f(x) = 5x²
f(10) = 5(10)² = 5(100) = 500
f'(x) = 10x
f'(10) = 10(10) = 100
Now, find the line that passes through (10, 500) and has a slope of 100
y - y₁ = m(x - x₁)
y - 500 = 100(x - 10)
y - 500 = 100x - 1000
y = 100x - 500
Answer:
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Step-by-step explanation:
Answer:
c
Step-by-step explanation:
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If your given slope is - 35, your equation starts off as y = - 35x + b
Now we plug in the point given and solve for b.
- 3 = - 35(6) + b
- 3 = - 210 + b
207 = b
So your equation is:
y = - 35x + 207