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2 years ago

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Mathematics

1 answer:

asambeis [7]2 years ago

3 0

Answer:

38.25 units.

Step-by-step explanation:

The trapezoid is given with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)

When given vertices ( x1, y1), (x2, y2)

We use the formula:

√(x2 - x1)² + (y2 - y1)² to find the length of the sides of the Trapezoid

Side QR: Q(8, 8), R(14, 16)

= √(x2 - x1)² + (y2 - y1)²

= √(14 - 8)² + (16 - 8)²

= √6² + 8²

= √36 + 64

= √100

= 10 units

Side RS: R(14, 16), S(20, 16)

= √(x2 - x1)² + (y2 - y1)²

= √(20 - 14)² + (16 - 16)²

= √6² + 0²

= √36

= 6 units

Side ST : S(20, 16), T(22, 8)

= √(x2 - x1)² + (y2 - y1)²

= √(22 - 20)² + ( 8 - 16)²

= √2² + (-8)²

= √4 + 64

= √68

= 8.2462112512

≈ nearest hundredth = 8.25 units

Side QT, Q(8, 8), T(22, 8)

= √(x2 - x1)² + (y2 - y1)²

= √(22 - 8)² + (8 - 8)²

= √14² + 0²

= √196

= 14 units

The Perimeter of a Trapezoid is the sum of all it's sides.

P = QR + RS + ST + QT

P = (10 + 6 + 14 + 8.25) units

P = 38.25 units

Therefore, the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8) is 38.25units.

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Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

Let p = percentage of seniors who skip their classes.

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, test statistics = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that seniors skip more than 2% of their classes.

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<h3>Answer: (2,0)</h3>

Explanation:

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If you were to go clockwise, then everything flips and you'll ultimately end up pointing directly west. The length of the vector stays the same the whole time.

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