The x - intercept of 5x - 3y = 15 is (3, 0)
The y -intercept of 5x - 3y = 15 is (0, -5)
<h3><u>Solution:</u></h3>
Given equation is 5x - 3y = 15
<em><u>To find: x - intercept and y -intercept</u></em>
The x intercept is the point where the line crosses the x axis. At this point y = 0
The y intercept is the point where the line crosses the y axis. At this point x = 0.
<em><u>Finding x - intercept:</u></em>
To find the x intercept using the equation of the line, plug in 0 for the y variable and solve for x
So put y = 0 in given equation
5x - 3(0) = 15
5x = 15
x = 3
So the x - intercept is (3, 0)
<em><u>Finding y - intercept:</u></em>
To find the y intercept using the equation of the line, plug in 0 for the x variable and solve for y
So put x = 0 in given equation
5(0) - 3y = 15
-3y = 15
y = -5
So the y - intercept is (0, -5)
When answering things like this do the brackets first, is there are parenthesis in the brackets do those but keep it in the brackets and work regularly after
So basically... you divide the 3 to 2 and that's how you get the decimal. The decimal is... 0.666666666667
(p + q)⁵
(p + q)(p + q)(p + q)(p + q)(p + q)
{[p(p + q) + q(p + q)][p(p + q) + q(p + q)](p + q)}
{[p(p) + p(q) + q(p) + q(q)][p(p) + p(q) + q(p) + q(q)](p + q)}
(p² + pq + pq + q²)(p² + pq + pq + q²)(p + q)
(p² + 2pq + q²)(p² + 2pq + q²)(p + q)
{[p²(p² + 2pq + q²) + 2pq(p² + 2pq + q²) + q²(p² + 2pq + q²)](p + q)}
{[p²(p²) + p²(2pq) + p²(q²) + 2pq(p²) + 2pq(2pq) + 2pq(q²) + q²(p²) + q²(2pq) + q²(q²)](p + q)}
(p⁴ + 2p³q + p²q² + 2p³q + 4p²q² + 2pq³ + p²q² + 2pq³ + q⁴)(p + q)
(p⁴ + 2p³q + 2p³q + p²q² + 4p²q² + p²q² + 2pq³ + 2pq³ + q⁴)(p + q)
(p⁴ + 4p³q + 6p²q² + 4pq³ + q⁴)(p + q)
p⁴(p + q) + 4p³q(p + q) + 6p²q²(p + q) + 4pq³(p + q) + q⁴(p + q)
p⁴(p)+ p⁴(q) + 4p³q(p) + 4p³q(q) + 6p²q²(p) + 6p²q²(q) + 4pq³(p) + 4pq³(q) + q⁴(p) + q⁴(q)
p⁵ + p⁴q + 4p⁴q + 4p³q² + 6p³q² + 6p²q³ + 4p²q³ + 4pq⁴ + pq⁴ + q⁵
p⁵ + 5p⁴q + 10p³q² + 10p²q³ + 5pq⁴ + q⁵
