Answer:
0.17 s
Explanation:
Given:
Δy = 0.15 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
0.15 m = (0 m/s) t + ½ (9.8 m/s²) t²
t = 0.17 s
F=mgsinα –F(fr)=
= mgsinα - μmgcosα
a=F/m =g(sinα – μcosα)
=9.8(sin14-0.57•cos14)= -3.04 m/s²
v²=v₀²+2ad
v=sqrt{ v₀²+2ad} =
=sqrt{18²+2• (-3.04) •25}=13.1 m/
Answer:
It depends on the product of their mass and velocity
Explanation:
The momentum of a moving object is defined as the product of its mass and its moving velocity. So a same object would have larger momentum it's traveling faster, or gets heavier, and vice versa. In our case we don't have the exact value of speed and mass of both objects so we can't say which one has a greater momentum.
Answer:
true
Explanation:
this is fair to other people