The vertical components of velocity is 10.35 m/s and the horizontal component of velocity is 38.6 m/s
<h3>What are the components of velocity?</h3>
We know that velocity is a vector quantity, a vector often can be resolved into its components. The vertical components is V sinθ while the horizontal component is vcosθ.
Hence;
Vertical component = 40 m/s sin 15 degrees = 10.35 m/s
Horizontal component = 40 cos 15 degrees = 38.6 m/s
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The matter from the explosion can reach him, hitting him. He should be able to feel that.
The terminal velocity of gold sphere is 39.2 cm/s
<h3>What is terminal velocity?</h3>
Terminal velocity is the maximum velocity attainable for an object as it falls through a fluid.
<h3>How to calculate the terminal velocity of the gold sphere?</h3>
The terminal velocity of the gold sphere is given by v = 2gr²(ρ - σ)/9η where
- g = acceleration due to gravity = 9.8 m/s²,
- r = radius of sphere = 100 μm = 100 × 10⁻⁶ m = 10⁻⁴ m = 10⁻² cm,
- ρ = density of sphere = 19 g/cm³,
- σ = density of water = 1.0 g/cm³ and
- η = viscosity of water = 10⁻³ Pa-s
So, susbtituting the values of the variables into the equation, we have that
v = 2gr²(ρ - σ)/9η
v = 2 × 9.8m/s²× (10⁻² cm)²(19 g/cm³ - 1.0 g/cm³)/(9 × 10⁻³ Pa-s)
v = 2 × 9.8 m/s² × 10⁻⁴ cm² × (18 g/cm³)/(9 × 10⁻³ Pa-s)
v = 2 × 980 cm/s² × 10⁻⁴ cm² × 2 g/cm³/(1 × 10⁻³ Pa-s)
v = 3920 g/s² × 10⁻⁴/(1 × 10⁻³ Pa-s)
v = 392 cm/s × 10³ × 10⁻⁴
v = 392 × 10⁻¹ cm/s
v = 39.2 cm/s
So, the terminal velocity is 39.2 cm/s
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Answer:
29.4 N/m
0.1
Explanation:
a) From the restoring Force we know that :
F_r = —k*x
the gravitational force :
F_g=mg
Where:
F_r is the restoring force .
F_g is the gravitational force
g is the acceleration of gravity
k is the constant force
xi , x2 are the displacement made by the two masses.
Givens:
<em>m1 = 1.29 kg</em>
<em>m2 = 0.3 kg </em>
<em>x1 = -0.75 m </em>
<em>x2 = -0.2 m </em>
<em>g = 9.8 m/s^2 </em>
Plugging known information to get :
F_r =F_g
-k*x1 + k*x2=m1*g-m2*g
k=29.4 N/m
b) To get the unloaded length 1:
l=x1-(F_1/k)
Givens:
m1 = 1.95kg , x1 = —0.75m
Plugging known infromation to get :
l= x1 — (F_1/k)
= 0.1