F(5) = 1/4(2)^5
f(5) = 1/4 (32)
f(5) = 8
answer
A. 8
9514 1404 393
Answer:
top down: ∞, 0, 1, 0, ∞
Step-by-step explanation:
The equation will have infinite solutions when the left side and right side simplify to the same expression. This is the case for the first and last expressions listed.
2(x -5) = 2(x -5) . . . . expressions are already identical
x +2(x -5) = 3(x -2) -4 ⇒ 3x -10 = 3x -10 . . . the same simplified expression
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The equation will have no solutions when the x-coefficients are the same, but there are different added constants.
5(x +4) = 5(x -6) ⇒ x +4 = x -6 . . . not true for any x
4(x -2) = 4(x +2) ⇒ x -2 = x +2 . . . not true for any x
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The equation will have one solution when coefficients of x are different.
5(x +4) = 3(x -6) ⇒ 2x = -38 ⇒ x = -19
Sometimes it helps to put a number line in front of you. If one number is to the left of the other number on the number line, it's a lower number. If one number is to the right of the other number on the number line, it is greater.
-5 -4 -3 -2 -1 0 1 2 3 4 5
4 is a solution of x<-5
FALSE: 4 is not greater than -5
-3 is a solution of y>-2
FALSE: -3 is not greater than -2
y≤3 includes 3 as a possible solution
TRUE: 3 is less than OR EQUAL to 3
Hope this helps! :)
17)
18)
19)
20)
Step-by-step explanation:
17) The difference between a number and 8 is 11
Let number = x
then the equation will be:
Solving:
18) Nine less than a number is five.
Let number = x
then the equation will be:
Solving:
19) Seven is equal to a number plus 6
Let number = x
then the equation will be:
Solving:
20) The sum of a number and -4 is -18
Let number = x
then the equation will be:
solving:
Keywords: Algebraic Expressions
Learn more about Algebraic Expressions at:
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Answer:
The combination 9 mm, 6mm, 5mm will not form a triangle.
9 +6 = 15 > 5
6+5= 11 < 9
9+5 =14 > 6
Explanation :
because the side length of triangle does not obey triangle inequality theorem.
The triangle inequality theorem:
The sum of the lengths of any two sides of a triangle is greater than the length of the third side.