Hey guys, I'm relearning some Algebra and was confused about this problem. In the equation, the problem was divided by 3. This m akes sense because its easier to work with smaller numbers. However, after that the negative signs swapped. Why does this happen? I remember switching signs years ago when I learned it but now I can't remember the rule as to why. Thank you so much.
2 answers:
Answer:
That's optional
Step-by-step explanation:
Dealing with positive numbers is simpler that's why the equation was divided by -3.
Nonetheless, you can use:
-6x² - 5x + 1 = 0 too
You will get the same answer
D = (-5)² - 4(-6)(1)
D = 25 + 24 = 49
x = [-(-5) +/- sqrt(49)]/(2×-6)
x = [5 +/- 7]/(-12)
x = -2/-12 = ⅙
x = 12/-12 = -1
Answer and Step-by-step explanation:
The signs didn't really "swap". Instead, the whole function was divided by -1, or we could say the function was divided by -3. That would turn:
-18x² - 15x + 3 = 0
into
(-18 / -3)x² - (15 / -3)x + (3 / -3) = 0
6x² + 5x - 1 = 0
And that gives the "swapped signs".
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One question before I give my answer , Where did it say she stopped?