Answer:
Step-by-step explanation:
Given the inequality solved by a student expressed as:
-6v>42
To get v, follow the simple steps
Step 1: multiply both sides by -1
-6v>42
-1(-6v)<-1(42)
6v < 42 (Note that when you multiply both sides of an inequality by a negative sign, the inequality sign will change)
Step 2: Divide through by 6
6v < 42
6v/6 < 42/6
v < 7
Hence the range of values of v are the values of v less than 7
Since we are not given the options, you can compare the solution given with that of the student to figure out the error. The major error that may happen is the different not changing the inequality sign after multiplying or dividing with a negative value as shown.
Answer:
x = 7
y = 0
Step-by-step explanation:
→To solve this, you can use the elimination method. To do this, you must have one set of variables that can cancel each other out. In the problem given, we already have positive 4x and -4x, making them cancel out:
4x + 9y = 28
-4x - y = -28
__________
8y = 0
y = 0
<u>→Plug in 0 for y, into an equation:</u>
-4x - 0 = -28
-4x = -28
x = 7
Answer:
1. |y| sqrt(10)
2. |x| sqrt(x)
3. a^2 sqrt(a)
4. 4 |y|^3 sqrt(3)
5. 1/4 *|x| sqrt(3x)
Step-by-step explanation:
1. sqrt(10y^2)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(y^2) sqrt(10)
|y| sqrt(10)
We take the absolute value of y because -y*-y = y^2 and the principle square root is y
2. sqrt(x^3)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(x^2) sqrt(x)
|x| sqrt(x)
3. sqrt(a^5)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(a^4) sqrt(a)
a^2 sqrt(a)
4. sqrt(16 y^7)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(16) sqrt(y^6)sqrt(y)
4 |y|^3 sqrt(3)
5. sqrt(3/16x^3)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(1/16) sqrt(x^2)sqrt(3x)
1/4 *|x| sqrt(3x)
