The area of the shape shown in the image which is in the shape of kite figure is 168 squared centimeters.
<h3>What is the area of the kite figure?</h3>
The area of the kite figure is half of the product of its diagonals. Area of kite figure can be find out using the following formula.
Here, p and q are the diagonals of the kite.
The length of the first diagonal of the kite figure is,
p=6+15
p=21 cm
The length of the second diagonal of the kite figure is,
q=8+8
q=16 cm
Thus, the area of kite figure is:
Thus, the area of the shape shown in the image which is in the shape of kite figure is 168 squared centimeters.
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Answer:
5y+6x-40=0
Step-by-step explanation:
y-2=-6/5(x-5)
5y-10=-6(x-5)
5y-10=-6x+30
5y+6x-10-30=0
5y+6x-40=0
F(-4x)=4x+4x
set up the composite function and simplify!
Answer:
x + y = 84
Step-by-step explanation:
Given
x : y : z = 5 : 1 : 3, then
= 5 ( multiply both sides by y )
x = 5y ←
and = ( cross- multiply )
3y = z
Substitute z = 3y into z - y = 28
3y - y = 28
2y = 28 ( divide both sides by 2 )
y = 14 ← ←
Substitute y = 14 into x = 5y
x = 5 × 14 = 70 ← ←
Substitute y = 14 into z - y = 28
z - 14 = 28 ( add 14 to both sides )
z = 42 ← ←
Thus x = 70, y = 14 and z = 42
Hence x + y = 70 + 14 = 84
The slope of the line parallel to the line –x + 3y = 6 is a 1/3 option (A) 1/3 is correct.
<h3>What is the slope?</h3>
The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).
It is given that:
The equation of the line:
–x + 3y = 6
Write the equation in standard form:
y = x/3 + 6/3
y = x/3 + 2
m = 1/3
The slope of the line parallel to the line –x + 3y = 6
M = 1/3
Thus, the slope of the line parallel to the line –x + 3y = 6 is a 1/3 option (A) 1/3 is correct.
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