<span>hello :
</span>F(x) = (x-3) (x+8) (x-11)
F(x) =0
<span>x-3= 0 or x+8=0 or x-11 = 0
x=3 or x=-8 or x=11
</span><span>the zeros of the polynomialare : 3 , -8 , 11 </span><span>
</span>
Answer:
Step-by-step explanation:
Hello,
<em>"Ray says the third-degree polynomial has four intercepts. Kelsey argues the function can have as many as three zeros only."</em>
We know that Kelsey is right, a polynomial of degree 3 has maximum 3 zeroes, so it means that the graph of this polynomial has maximum 3 x-intercepts.
<u>So how Ray can be right too?</u>
we need to think of y-intercept, if we add the y-intercept then Ray can be right too,
as you can see in one example below
there are 3 x-intercepts and 1 y-intercept.
This being said, Ray is not always right. For instance
has only 1 zero (multiplicity 3) its graph has only 1 intercept in the point (0,0)
hope this helps
Answer:
b) 5
Step-by-step explanation:
f(x) = x² + 1
f(2) = (2)² + 1
= 4 + 1
= 5
Answer:
VW = 7
Step-by-step explanation:
Because it is a parallelogram, UX = VW
x-4 = 2x - 15
11 = x
VW = 2 x 11 - 15
VW = 7