1 and 2 are equations and 3 is a solution
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
Answer:
-6r+6
Step-by-step explanation:
Given data
We are given the expression
8-(6r+2)
let us expand it by opening the bracket
=8-6r-2
collect like terms
=8-2-6r
=6-6r
rearrange
=-6r+6
Hence option A is correct
Answer:
What rays?
Step-by-step explanation:
Is it the new album of BtS?
Answer:
-9.8n + 11.1
Step-by-step explanation:
1. Combine like terms
-5.8n - 4n = -9.8n
3.1 + 8 = 11.1
2. -9.8n +11.1
