To calculate the tax multiply $860 by .06 (6%) to get $34.40.
To calculate the total amount you'll pay add $34.40 to $860 to get $894.40.
Answer:
See answer below
Step-by-step explanation:
The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.
i) x∈AnB if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.
ii) (I will abbreviate "if and only if" as "iff")
x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.
iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).
iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).
Answer:
curtiss can buy 7 pounds of pistachios
Step-by-step explanation:
5 cappuccinos x $5 = 25, 32 - 25=7
Answer:
The expression is not equivalent to other three is 9(n-9) .
Option (B) is correct .
Step-by-step explanation:
Take first expression
= -9 -7n + 16n
= 9n-9
Take second expression
= 9(n-9)
= 9 × n - 9 × 9
= 9n - 81
Take third expression
= n-9+8n
= 9n-9
Take fourth expression
= 9n-9
Therefore expression is not equivalent to other three is 9(n-9) .
Option (B) is correct .
Answer:
TRUE
Step-by-step explanation:
<h2>
<em><u>TRUE </u></em></h2>