All categories

2 years ago

What would be themost approriate cudtormy unit to measure the weight of a paper clip. ounces or pounds?

Mathematics

1 answer:

Dmitrij [34]2 years ago

6 0

Ounces would be the most accurate/appropriate to use with such a small item

You might be interested in

If a 6-foot man casts an 8-foot shadow, how tall is a tree that casts a 24-foot shadow?

noname [10]

26 , 8-6=2 so you do 24+6

8 0

2 years ago

If f(x) = -1, solve for x.

weeeeeb [17]

Answer:

No solution.

Explanation:

The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace f(x) with 0 and solve for x.

3 0

2 years ago

Best has knitted 5/8 of the scarf she is making has she needed more than one half of the scarf can't find the equivalent fractio

BabaBlast [244]

To compare 5/8 and 1/2, you will need to create fractions that have the same denominator. 1/2 is the same as 4/8.

5/8 is greater than 4/8, so she had knitted more than 1/2.

4 0

2 years ago

Find the value of n, correct to 4 significant figures.

Law Incorporation [45]

Answer:

6.708

Step-by-step explanation:

Y varies directly as the square of x (Given)

$\implies y\:\alpha \:x^2$ ......(1)

Y varies inversely as the square root of z (Given)
$\implies y\:\alpha\: \frac{1}{\sqrt z}$ ......(2)

Combining (1) & (2), we find:

$y\:\alpha \:\frac{x^2}{\sqrt z}$

$\implies y=\frac{kx^2}{\sqrt z}$ (Where k is constant of proportionality).....(3)

Now, when y = 2, x = 3 and z = 4, we find the value of k i.e. constant.

$2=\frac{k(3)^2}{\sqrt 4}$

$\implies 2=\frac{k(9)}{2}$

$\implies k =\frac{4}{9}$

Plugging the value of k in (3), we find:

$y=\frac{4x^2}{9\sqrt z}$ ....(4)

Next, in equation (4), plug y = 5, x = n and z = 16 and obtain the value of n by solving it.

$5=\frac{4(n)^2}{9\sqrt {16}}$

$\implies 5=\frac{4(n)^2}{9(4)}$

$\implies 5=\frac{(n)^2}{9}$

$\implies 5(9)=(n)^2$

$\implies 45=(n)^2$

$\implies n=\sqrt{45}$

$\implies n=6.70820393$

$\implies n\approx 6.708$

7 0

1 year ago

P is a prime number. Show that p²+6 could be either even or odd

storchak [24]

p ² + 6 is even if p ² is even (the sum of two even numbers is even), and this happens only if p itself is even, i.e. if p = 2 since 2 is the only even prime.

All other primes p are odd, so p ² would be odd, and adding 6 would not change that (odd + even = odd).

6 0

2 years ago