The maximum value of the objective function is 26 and the minimum is -10
<h3>How to determine the maximum and the minimum values?</h3>
The objective function is given as:
z=−3x+5y
The constraints are
x+y≥−2
3x−y≤2
x−y≥−4
Start by plotting the constraints on a graph (see attachment)
From the attached graph, the vertices of the feasible region are
(3, 7), (0, -2), (-3, 1)
Substitute these values in the objective function
So, we have
z= −3 * 3 + 5 * 7 = 26
z= −3 * 0 + 5 * -2 = -10
z= −3 * -3 + 5 * 1 =14
Using the above values, we have:
The maximum value of the objective function is 26 and the minimum is -10
Read more about linear programming at:
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To find slope use the equation (y2 - y1) / (x2 - x1)
5 - 4 / 2--2
1/-4
The slope is -1/4
Hope this helps :)
Answer:
17 + 3n
Step-by-step explanation:
20, 23,26 ..............
This is an arithmetic series
First term = a = 20
Common difference = second term - first term
d = 23 - 20 = 3
nth terms = a + (n-1)*d
= 20 + (n -1) *3
= 20 + n*3 - 1*3
= 20 + 3n - 3
= 20 - 3 + 3n
= 17 + 3n
8x + 4 = 5x - 11
Subtract 5x from both sides:
3x + 4 = -11
Subtract 4 from both sides:
3x = -15
Divide both sides by 3:
x = -5
Answer : x = -5
Answer:
Step-by-step explanation:
To solve this problem, we can use the area of a circle formula:
<em>A = area</em>
<em>r = radius</em>
Lets plug the values into the equation:
Calculate 
Multiply 
and 9 together
The area of the truck wheel is
