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2 years ago

In rhombus fmkw mk=12 fk= 16 m

Mathematics

1 answer:

gizmo_the_mogwai [7]2 years ago

4 0

If it is area your looking for.

Area = product of diagonal lengths divided by 2

Area = 12* 16 /2

=192/2 = 96.

IF it is the side length of the rhombus:

apply Pythagoras theorem since the diagonals always meet at 90°.

L =√(12² + 16²)

L= √400 = 20

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