Answer:
1. The number of mole of each element present = 1mole of Na, 1mole of N and 3moles of O
2. The empirical formula is NaNO3.
3. The name of the compound is sodium trioxonitrate (V)
Explanation:
Mass of Na = 0.360g
Mass of N = 0.220g
Mass of O = 0.752g
Number of mole present for each elements is given below:
For Na:
Molar Mass of Na = 23g/mol
Number of mole = Mass /Molar Mass
Number of mole of Na = 0.360/23 = 0.0157mol
For N:
Molar Mass of N = 14g/mol
Number of mole = Mass /Molar Mass
Number of mole of N = 0.220/14 = 0.0157mol
For O:
Molar Mass of O = 16g/mol
Number of mole = Mass /Molar Mass
Number of mole of = 0.752/16 = 0.047mol
Next we'll divide the moles of Na, N, and O obtained by the smallest mole among them i.e 0.0157
For Na:
0.0157/0.0157 = 1
For N:
0.0157/0.0157 = 1
For O:
0.047/0.0157 = 3
The number of mole of each element present = 1mole of Na, 1mole of N and 3moles of O
Therefore, the empirical formula is NaNO3.
The name of the compound is sodium trioxonitrate (V)