What are the slopes of the asymptotes of a hyperbola with equation (y-2)^2/1^2 - (x-4)^2/3^2 = 1?
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Answer:
For the given expression:
Step-by-step explanation:
Here, the given expression in statement form is given as:
5 X minus Y equals 6 + negative 2 X plus Y = 8
Now, converting the given statement mathematically, we get:
5X - Y = 6 + (-2X) + Y = 8
Now, considering first and the last terms,we get:
5 X - Y = 8 .... (1)
and , considering second and the last terms,we get:
6 + (-2X) + Y = 8 or, -2X + Y = 2 ......... (2)
Adding (1) and (2) , we get:
5 X - Y - 2 X + Y = 8 + 2
or, 3 X = 10
or, X = 10/3 = 3.34
Now, 5X - Y = 8
or,
Hence, for the given expression: