-two significant figures
-four significant figures
-One significant figure
-four significant figures
-two significant figures
-three significant figures
-three significant figures
what is interfacial tension in liqui liquid extraction?
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<em>Hence</em><em>,</em><em> </em><em>84</em><em>°</em><em>F</em><em> </em><em>is</em><em> </em><em>30</em><em>°</em><em>C</em><em> </em><em>in</em><em> </em><em>Celsius</em><em>.</em><em>.</em>
Answer:
10.5g
Explanation:
First, let us calculate the number of mole of NaHCO3 present in the solution. This is illustrated below:
Volume = 250mL = 250/1000 = 0.25L
Molarity = 0.5M
Mole =?
Molarity = mole /Volume
Mole = Molarity x Volume
Mole = 0.5 x 0.25
Mole = 0.125 mole
Now, we shall be converting 0.125 mole of NaHCO3 to grams to obtain the desired result. This can be achieved by doing the following:
Molar Mass of NaHCO3 = 23 + 1 + 12 +(16x3) = 23 + 1 +12 +48 = 84g/mol
Number of mole of NaHCO3 = 0.125 mole
Mass of NaHCO3 =?
Mass = number of mole x molar Mass
Mass of NaHCO3 = 0.125 x 84
Mass of NaHCO3 = 10.5g
Therefore, 10.5g of NaHCO3 is needed.
