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2 years ago

What resources should the scientist use to research water pollution?

1 answer:

3 0

A scientist needs to check several parameters before coming to a conclusion about the amount of water pollution. The scientists needs to check the amount of dissolved oxygen in the water, temperature of the water, the clarity of the water, the PH level of the water and also the amount of bacteria present in the water. There may be other criteria’s, but the mentioned ones are enough to gauge the amount of pollution in the water. Scientists often takes fish and aquatic plants from the water to be tested to check the amount of pollution indirectly affecting these species.

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Salt in crude oil must be removed before the oil undergoes processing in a refinery. The

irina1246 [14]

Answer:

$\large \boxed{0.64 \, \%}$

Explanation:

Assume you are using 1 L of water.

Then you are washing 4 L of salty oil.

1. Calculate the mass of the salty oil

Assume the oil has a density of 0.86 g/mL.

$\text{Mass of oil} = \text{4000 mL} \times \dfrac{\text{0.86 g}}{\text{1 mL}} = \text{3440 g}$

2. Calculate the mass of salt in the salty oil

$\text{Mass of salt} = \text{3440 g} \times \dfrac{\text{5 g salt}}{\text{100 g oil}} = \text{172 g salt}$

3. Calculate the mass of salt in the spent water

$\text{Mass of salt} = \text{1000 g water} \times \dfrac{\text{15 g salt}}{\text{100 g water}} = \text{150 g salt}$

4. Mass of salt remaining in washed oil

Mass = 172 g - 150 g = 22 g

5. Concentration of salt in washed oil

$\text{Concentration} = \dfrac{\text{22 g}}{\text{3440 g}} \times 100 \, \% = \mathbf{0.64 \, \%}\\\\\text{The concentration of salt in the washed oil is $\large \boxed{\mathbf{0.64 \, \%}}$}$

3 0

2 years ago

What type of bonds are shown in this diagram?

qaws [65]

Answer:

What type of bonds are shown in this diagram?

A: covalent bonds

B: ionic bonds

C: hydrogen bonds

D: metallic bonds

(answer) metallic bonds

In what type of bonds do atoms join together because their opposite charges attract each other?

A: metallic bonds and covalent bonds

B: metallic bonds and ionic bonds

C: ionic bonds and covalent bonds

D: ionic bonds and hydrogen bonds

(answer) ionic bonds and hydrogen bonds

What types of bonds are shown in this diagram?

A: covalent bonds

B: ionic bonds

C: hydrogen bonds

D: metallic bonds

(answer) hydrogen bonds

Which statement best describes the types of bonds shown in the diagram?

A: an ionic bond; the hydrogen chloride molecule has an electrical charge

B: an ionic bond; a hydrogen ion is bonding with a chlorine atom

C: a covalent bond; the hydrogen atom’s two electrons are being shared with the chlorine atom

D: a covalent bond; the hydrogen atom’s single electron is being shared with the chlorine atom

(answer) a covalent bond; the hydrogen atom’s single electron is being shared with the chlorine atom

Which of the following bonds is the strongest?

A: hydrogen bonds

B: metallic bonds

C: valence bonds

D: covalent bonds

(answer)

Explanation:

UwU

3 0

1 month ago

Read 2 more answers

Vitamin D is produced in the skin when 7-dehydrocholesterol reacts with UVB rays (ultraviolet B) having wavelengths between

goblinko [34]

The energy range expected is 6.6 × 10^-19 J < E < 7.33 × 10^-19 J

The energy of the photon is given by;

E = hc/λ

E = energy of the photon

h = Plank's constant

c = speed of light

λ = wavelength of light

For the upper boundary range;

E = ?

h = 6.6 × 10^-34 Js

c = 3 × 10^8 m/s

λ = 270 × 10^-9

E = 6.6 × 10^-34 Js × 3 × 10^8 m/s / 270 × 10^-9

E = 7.33 × 10^-19 J

For the lower range;

E = ?

h = 6.6 × 10^-34 Js

c = 3 × 10^8 m/s

λ =300 × 10^-9

E = 6.6 × 10^-34 Js × 3 × 10^8 m/s / 300 × 10^-9

E = 6.6 × 10^-19 J

Hence, the energy range 6.6 × 10^-19 J < E < 7.33 × 10^-19 J

Learn more: brainly.com/question/24857760

8 0

1 year ago

Prediction for Scandium (II) and Cl

SCORPION-xisa [38]

Answer:

(a) Eka-aluminum and gallium are two names of the same element as Eka-Aluminium has almost exactly the same properties as the actual properties of the gallium element. The properties: atomic mass, density, melting point, formula of chloride and formula of oxide are almost the same.

Explanation:

Scandium - Eka boron.

(ii) Gallium - Eka aluminium.

(iii) Germanium - Eka silicon.

3 0

2 years ago

Simple cell?

poizon [28]

Answer:

I don't know..but plz follow me

4 0

2 years ago