The average force applied to the ball= 106.7 N
Explanation:
Force is given by
f= ΔP/t
ΔP= change in momentum= m Vf- m Vi
m= mass =0.2 kg
Vf= final velocity= 12 m/s
Vi=initial velocity= -20 m/s ( negative because it is going towards the wall which is treated as negative axis)
t= time= 60 ms= 0.06 s
now ΔP= 0.2 [ 12-(-20)]
ΔP=0.2 (32)=6.4 kg m/s
now force F= ΔP/t
F= 6.4/0.06
F=106.7 N
Explanation:
003 (part 1 of 2)
Pressure is force divided by area.
P = F / A
P = (117 kg × 9.8 m/s²) / (2 × (0.05 m)²)
P = 229,320 Pa
003 (part 2 of 2)
There are approximately 6895 Pa in 1 psi.
P = 229,320 Pa × (1 psi / 6895 Pa)
P = 33.3 psi
004 (part 1 of 2)
Since the collisions are elastic, the angle of reflection is the same as the angle of incidence (it bounces off at the same angle).
Impulse = change in momentum
F Δt = m Δv
F (36 s) = (300 × 0.003 kg) (5.2 sin 57° m/s − (-5.2 sin 57° m/s))
F = 0.218 N
004 (part 2 of 2)
Pressure is force over area.
P = F / A
P = 0.218 N / 0.712 m²
P = 0.306 N/m²
Answer:11
Explanation: because is the number that repeted 2 times