2 years ago

4 less than the product of one and a number z

Mathematics

2 answers:

Doss [256]2 years ago

5 0

Answer:

it's 1z-4

Step-by-step explanation:

4 = 4

(less than) = subtraction

(product of) = multiplication

one = 1

Z = Z

do a switcheroo

which then becomes : (1)(z)(-)(4)

(product of) (one) and a (number z) = 1 multiplied by z

4 is less than = - 4 because it's less than

AleksAgata [21]2 years ago

3 0

Answer:

z - 4

Step-by-step explanation:

Step 1: Convert "4 less"

-4

Step 2: Convert "Product of one and a number z"

1 · z

Step 3: Combine

z - 4

You might be interested in

It's all on the picture please answer it

zubka84 [21]

14?
17-12=5
5x2=10
10+4 =14

7 0

2 years ago

Read 2 more answers

5x+14<4 or -2(x-8)<-2

Kitty [74]

Answer:

Step-by-step explanation:

5x+14<4 or -2(x-8)<-2

-14 -14 -2x+16<-2

5x<-10 -16 -16

÷5 ÷5 -2x<-18

x<-2 ÷-2 ÷-2

x>9 (sign changes because you divide by a negative number)

x<-2 or x>9

7 0

2 years ago

Solve the following proportion for v. v/12=13/7 Round your answer to the nearest tenth. Plz help

Liula [17]

Answer:

22.3

Step-by-step explanation:

divide 13/7 = 1.86

multiply 1.86x12 = 22.3

5 0

3 years ago

1 1 Charlotte has 203 feet of plastic pipe. She cuts off a 35-foot length and then a 6-foot length. If she now needs a 10-foot p

oee [108]

Answer:

After subtracting, there should be 10.5833333 foot piece left. The remaining piece will do, there will be 0.5833333 foot left of a piece.

Step-by-step explanation:

25 1/3 - (8.5 + 6.25)

25 1/3 - 14.75

=10.5833333

7 0

2 years ago

Which solution to the equation 1/x-1 = x-2/2x^2-2 is extraneous

melamori03 [73]

<u>Solution-</u>

The equation given here,

$\frac{1}{x-1} =\frac{x-2}{2x^2-2}$

$\Rightarrow 2x^2-2=(x-1)(x-2)$

$\Rightarrow 2x^2-2=x^2-3x+2$

$\Rightarrow x^2+3x-4=0$

$\Rightarrow x^2 +4x-x-4=0$

$\Rightarrow (x-1)(x+4)=0$

$\Rightarrow x=1 \ and -4$

But, at x=1, $\frac{1}{x-1} \ and \ \frac{x-2}{2x^2-2}$ becomes infinity so it can't be a solution to the equation.

∴ x=1 is the extraneous solution of the equation

3 0

2 years ago

Read 2 more answers