Answer:
You increase the acceleration of the car.
Complete question:
A train has an initial velocity of 44m/s and an acceleration of -4m/s². calculate its velocity after 10s ?
Answer:
the final velocity of the train is 4 m/s.
Explanation:
Given;
initial velocity of the train, u = 44 m/s
acceleration of the train, a = -4m/s² (the negative sign shows that the train is decelerating)
time of motion, t = 10 s
let the final velocity of the train = v
The final velocity of the train is calculated using the following kinematic equation;
v = u + at
v = 44 + (-4 x 10)
v = 44 - 40
v = 4 m/s
Therefore, the final velocity of the train is 4 m/s.
Answer:
The correct answer is "6666.67 N".
Explanation:
The given values are:
Mass,
m = 0.100
Relative speed,
v = 4.00 x 10³
time,
t = 6.00 x 10⁻⁸
As we know,
⇒
On substituting the given values, we get
⇒
⇒
Answer:
1.8 cm
Explanation:
= mass of the singly charged positive ion = 3.46 x 10⁻²⁶ kg
= charge on the singly charged positive ion = 1.6 x 10⁻¹⁹ C
=Potential difference through which the ion is accelerated = 215 V
= Speed of the ion
Using conservation of energy
Kinetic energy gained by ion = Electric potential energy lost
= Radius of the path followed by ion
= Magnitude of magnetic field = 0.522 T
the magnetic force on the ion provides the necessary centripetal force, hence