We find the first differences between terms:
7-4=3; 12-7=5; 19-12=7; 28-19=9.
Since these are different, this is not linear.
We now find the second differences:
5-3=2; 7-5=2; 9-7=2. Then:
Since these are the same, this sequence is quadratic.
We use (1/2a)n², where a is the second difference:
(1/2*2)n²=1n².
We now use the term number of each term for n:
4 is the 1st term; 1*1²=1.
7 is the 2nd term; 1*2²=4.
12 is the 3rd term; 1*3²=9.
19 is the 4th term; 1*4²=16.
28 is the 5th term: 1*5²=25.
Now we find the difference between the actual terms of the sequence and the numbers we just found:
4-1=3; 7-4=3; 12-9=3; 19-16=3; 28-25=3.
Since this is constant, the sequence is in the form (1/2a)n²+d;
in our case, 1n²+d, and since d=3, 1n²+3.
The correct answer is n²+3
A=1/2bh
b=8+h
A=384
384=1/2(bh)
times 2
768=bh
sub
768=b(8+b)
768=8b+b^2
minus 768 both sides
0=b^2+8b-768
factor
0=(b-24)(b+32)
set to zero
b-24=0
b=24
b+32=0
minus 32
b=-32
false, legnths cannot be negative
b=24
24=8+h
minus 8
16=h
base=24ft
altetude=16ft
Answer:
Between 0 and 1
Step-by-step explanation:
The given expresion is
Recall that:
We apply this property of exponents to get;
We rewrite to obtain a positive index as:
Therefore the value of the expression is between 0 and 1.
Answer:
15
Step-by-step explanation:
