For which interval is the average rate of change of f(x) negative?
2 answers:
The Average Rate of Change<span> function describes the average rate at which one quanity is changing with respect to something else changing.
</span><span> For this case, the first thing you should do is observe the intervals for which the function decreases.
Remember that the definition of average rate of change is given by:
</span>
<span> For AVR to be negative, it must necessarily pass:
</span>
<span>
The interval that meets both conditions is:
x = 0 to x = 2.5
Answer:
x = 0 to x = 2.5
option 3</span>
</span><span> For this case, the first thing you should do is observe the intervals for which the function decreases.
Remember that the definition of average rate of change is given by:
</span>
<span> For AVR to be negative, it must necessarily pass:
</span>
The interval that meets both conditions is:
x = 0 to x = 2.5
Answer:
x = 0 to x = 2.5
option 3</span>
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Answer:
Step-by-step explanation:
Remember the general form of a linear equartion: y=mx + b, where m is the slope and b is the y-intercept (the value of y when x = 0).
The equation of line v (y=9x+1) has a slope of 9. A perpendicular line with have a slope equal to the negative inverse of the reference line. So the line we want will have a slope of -(1/9). That gives us y = -(1/9)x + b. Any vale of b will produce a line that is perpendicular. But we want a line that goes through point (3,-2). All we need to do is find a value for b that will make that wish come true.
Use the point (3,-2) in y = -(1/9)x + b and solve for b:
y = -(1/9)x + b
-2 = -(1/9)*(3) + b
-2 = -(1/3) + b
b = - 1 2/3, or -(5/3)
The equation is y = -(1/9)x + - (5/3)
