Weight percentage of nitrogen can be calculated using the following rule: weight percentage of nitrogen = (weight of nitrogen / weight of urea) x 100
From the periodic table: molecular mass of carbon = 12 grams molecular mass of nitrogen = 14 grams molecular mass of hydrogen = 1 grams molecular mass of oxygen = 16 grams
therefore: mass of nitrogen in urea = 2(14) = 28 grams mass of urea = 12 + 2(14) + 4(1) + 16 = 60 grams
Substitute with the masses in the equation to get the percentage: weight percentage of nitrogen = (28/60) x 100 = 46.667%
The temperature of the air at this given elevation will be 53.32425°C
Explanation:
We can calculate the final temperature through the combined gas law. Therefore we will need to know 1 ) The initial volume, 2 ) The initial temperature, 3 ) Initial Pressure, 4 ) Final Volume, 5 ) Final Pressure.
Initial Volume = 1.2 L ; Initial Temperature = 25°C = 298.15 K ; Initial pressure = 1.0 atm ; Final Volume = 1.8 L ; Final pressure = 0.73 atm
We have all the information we need. Now let us substitute into the following formula, and solve for the final temperature ( T ),
PV / T = PV / T,
T = PVT / PV,
T = 0.73 atm 1.8 L 298.15 K / 1 atm 1.2 L = ( 0.73 1.8 298.15 / 1 1.2 ) K = 326.47425 K,