Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:

8x-10 = x^2+12x+30

Group all terms together on the right side. To do this, add -8x+10 to both sides. Then 0 = x^2 +4x +40. You must now solve this quadratic equation for x, if possible. I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.

If you have a graphing calculator, please graph 8x-10 and x^2+12x+30 on the same screen. You will see two separate graphs that do NOT intersect. This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.

6 0

3 years ago

3. Askating rink charges a group fate of $9 plus a fee to rent each pair of skates. A family rents 7 pairs of skates and pays a

ddd [48]

Answer:

Step-by-step explanation:

Let the rental is x

<u>The total is, the equation:</u>

7x + 9 = 30
7x = 21
x = 3

Each skate rental is $3

4 0

2 years ago

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