Answer:
3rd one is no. the others are all yes
For each x value, add 3 to get y values.
0+3=3
2+3=5
4+3=7
6+3=9
Final answers, respectively: 3,5,7,9
The quadrants in which all the coordinates given are located is; As explained below.
<h3>How to Identify Quadrants in coordinates?</h3>
1) (2, 4) is located in Quadrant I where both x and y-values are positive.
2) (0, -3) is located in Quadrant II where x - values are positive but y-values are negative.
3) (-1, 1/2) is located in Quadrant IV.
4) (-2 1/2, -7) is located in Quadrant III where x and y values are both negative.
5) (0, 6) is located in Quadrant I where both x and y-values are positive.
6) (-5, 0) is located in Quadrant IV where x is negative but y is positive.
Read more about Quadrant Coordinates at; brainly.com/question/863849
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Rewrite the given quadratic equation in standard form: Kx 2 + 2x - 1 = 0
Discriminant = 4 - 4(K)(-1) = 4 + 4K
For the equation to have two real solutions, the discriminant has to be positive. Hence we need to solve the inequality 4 + 4K > 0.
The solution set to the above inequality is given by: K > -1 for which the given equation has two real solutions.
Answer:
(13 x + 6) (x - 2)
Step-by-step explanation:
Factor the following:
13 x^2 - 20 x - 12
Factor the quadratic 13 x^2 - 20 x - 12. The coefficient of x^2 is 13 and the constant term is -12. The product of 13 and -12 is -156. The factors of -156 which sum to -20 are 6 and -26. So 13 x^2 - 20 x - 12 = 13 x^2 - 26 x + 6 x - 12 = x (13 x + 6) - 2 (13 x + 6):
x (13 x + 6) - 2 (13 x + 6)
Factor 13 x + 6 from x (13 x + 6) - 2 (13 x + 6):
Answer: (13 x + 6) (x - 2)