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2 years ago

Sin^2x + sin^2x + cos²x

Mathematics

1 answer:

Nezavi [6.7K]2 years ago

7 0

Answer:

Answer:

A. 2 sinx cosx - 1 + 2 sin^2 x.

Step-by-step explanation:

sin2x = 2 sinx cosx

cos2x = cos^2x - sin^2x

So sin2x - cos2x = 2 sinx cosx - ( cos^2x - sin^2x)

But cos^2 x = 1 - sin^2 x, so we have:

2 sinx cosx - (1 - sin^2 x - sin^2x)

= 2 sinx cosx - 1 + 2 sin^2 x.

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Ray Of Light [21]

Answer:

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Step-by-step explanation:

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Description:

The first step is to simplify the equation provided. So in this case the equation is 4 x (8 + 5) + 9. After that you will get your answer as =52x+9. So in this case 4 x (8 + 5) + 9 = =52x+9.

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1 year ago

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Express in terms of logarithm without exponents

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\\ \quad \\
% Logarithm of rationals
\\ \quad \\
% Logarithm of exponentials
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-----------------------------\\\\
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