<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
Step-by-step explanation:
Distance =
Here X is -3
So,
Point Y = -3 + 6.5 = 3.5
Hope this helped!
<h3>~AH1807</h3>
Answer:
12 combinations
Step-by-step explanation:
The answer to this question would be true.
An odd number wouldn't have any 2 in their factor because it is the definition of odd number, can't be divided by 2. Since they have no probability of having factor 2, then their GCF would not become an even number.
Answer:
<em><u>see</u></em><em><u> </u></em><em><u>below</u></em><em><u>:</u></em><em><u>-</u></em>
Step-by-step explanation:
- Convert the mixed fractions into improper fractions.