Write a two-column proof for the following conjuncture. You may not need to use all of the rows of the two-column table provided
below. You may also add additional rows if needed given parallelogram ABCD
(Given 7 Columns on Assignment)
Prove: angle A and angle B are supplementary
Angle B and angle C are supplementary.
1 answer:
Answer:
Given ABCD be a parallelogram
Then, AD // BC and AB is a transversal.
Because of the sum of the interior angles on the same side of the transversal is 180°
So, ∠A + ∠B = 180°
∴ Angle A and angle B are supplementary.
<u>Also</u>,
AB // CD and CB is a transversal.
Because of the sum of the interior angles on the same side of the transversal is 180°
So, ∠B + ∠C = 180°
∴ Angle B and angle C are supplementary.
You might be interested in
61.67$ because you round the 7 up to the nearest hundredth
I think Its 6.............
Here we can simplify the product by multiply the square root 2 with square root 2 first.
=3*2
=6
So answer is 6
The x-intercept is + 6 and the y-intercept is + 10
umm, i the the desuetude what no one sec.