Answer:
a) A. The population must be normally distributed
b) P(X < 68.2) = 0.7967
c) P(X ≥ 65.6) = 0.3745
Step-by-step explanation:
a) The population is normally distributed having a mean () = 64 and a standard deviation () =
b) P(X < 68.2)
First me need to calculate the z score (z). This is given by the equation:
but μ=64 and σ=19 and n=14, and
Therefore:
From z table, P(X < 68.2) = P(z < 0.83) = 0.7967
P(X < 68.2) = 0.7967
c) P(X ≥ 65.6)
First me need to calculate the z score (z). This is given by the equation:
Therefore:
From z table, P(X ≥ 65.6) = P(z ≥ 0.32) = 1 - P(z < 0.32) = 1 - 0.6255 = 0.3745
P(X ≥ 65.6) = 0.3745
P(X < 68.2) = 0.7967
Answer:
Reciprocal of 5/18 is 18/5.
5/18 x 18/5 = 90/90
= 1
Answer:
Using distribute property
0.5(8a)(a) + 0.5(6b)(a) + 4b
4a^2 + 3ab + 4b
Step-by-step explanation:
Answer:
a
Step-by-step explanation: