Answer: 3.2 * 10^-3 C
Explanation: In order to solve this problem we have to use the Coulomb force given by:
F=k*q^2/ d^2 where he consider the same charge for each point
so, we have
q^2= F*d^2/k= 1.137* (10 C*9*10m)^2/9*10^9 N*m^2/C^2)=3.2 * 10^-3 C.
Answer:
If the end of the tube is uncovered such that the air at the end of the tube can freely vibrate when the sound wave reaches it, then the end is referred to as an open end. If both ends of the tube are uncovered or open, the musical instrument is said to contain an open-end air column.
Explanation: hope this helps:)
Answer:
Explanation:
The direction of force will be in upward direction making an angle of θ with the vertical .
Reaction force R = mg - F cosθ
Friction force = μR
= .36 (mg - F cosθ )
Horizontal component of applied force
= F sinθ
For equilibrium
F sinθ = .36 (mg - F cosθ)
F sinθ + .36 F cosθ =.36 mg
F (sinθ + .36 cosθ) = .36 mg
F R( cosδsinθ +sinδ cosθ) = .36 mg ( Rcosδ = 1 . Rsinδ= .36 )
F R sin( θ+δ ) = . 36 mg
F = .36 mg / Rsin( θ+δ )
For minimum F , sin( θ+δ ) should be maximum
sin( θ+ δ ) = sin 90
θ+ δ = 90
Rsinδ / Rcosδ = .36
δ = 20⁰
θ = 70⁰ Ans
9514 1404 393
Answer:
1.114 kg/m³
Explanation:
The total mass of the air in the balloon and the balloon + cargo will be the mass of the displaced air. If d is the density of the air in the balloon, then we have ...
2910d +308 = 2910×1.22
Solving for d, we find ...
2910d = 2919(1.22) -308
d = 1.22 -308/2910
d ≈ 1.114 . . . kg/m³
The density of the hot air is about 1.114 kg/m³.
Explanation:
A wave having a frequency of 200 Hz means that 200 such waves pass through a point per second.