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2 years ago

If f(x) = 6x2 - 4 and g(x) = 2x + 2, find (f - g)(x).

Mathematics

2 answers:

Hunter-Best [27]2 years ago

8 0

6x^2-2x-6 is the correct answer

Dafna11 [192]2 years ago

7 0

Answer:

6x² - 2x - 6

Step-by-step explanation:

note (f - g)(x) = f(x) - g(x), thus

f(x) - g(x)

= 6x² - 4 - (2x + 2) ← distribute

= 6x² - 4 - 2x - 2 ← collect like terms

= 6x² - 2x - 6

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balandron [24]

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2 years ago

I made 10 and three fifths gallons of soup of which 6 and one quarter gallons was chicken noodle. How much was not chicken noodl

nata0808 [166]

Answer: 4 7/20 gallons

Step-by-step explanation:

Gallons of soup made = 10 3/5

Gallons that was chicken noodle = 6 1/4

The gallons that wasn't chicken noodle will be:

= 10 3/5 - 6 1/4

= 10 12/20 - 6 5/20

= 4 7/20

Therefore, 4 7/20 gallons wasn't chicken noodle.

8 0

2 years ago

Paul is 20 years old. He is four times older than his sister.

attashe74 [19]

Answer: Paul will be 30 years old

Step-by-step explanation:Let the age of her sister be x, then from the given data

=> 4x = 20

=> x = 5 years

The age of her sister is 5 years

In the second case, paul is twice as old as his sister

=> Age of paul = 2(x)

=> Age of paul = 10 years

Paul will be 10 years old when he is twice as old as his sister

3 0

11 months ago

Read 2 more answers

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side$

4 0

2 years ago

Round 26 to its greatest place value

Crank

26 27 28 29 30 so 25 24 23 22 21---so 30 is the awnser

6 0

2 years ago

Read 2 more answers