Given that,
s = √(2t + 1)
Time, t = 4 s
Acceleration , a = ??
Since,
Acceleration = velocity / time
Velocity = distance/ time
Acceleration = distance/ time²
s/t² = √(2t+1)/t²
putting t = 4 sec, we have
a = √(2*4+1)/4²
a = √(5)/16
a= 0.139 ft/s²
Therefore, acceleration of the given particle will be 0.139 feet/ second².
Answer:
( 1000 × 4 = 4,000) (800×3= 2400) (800×2=1600) the answer is 1600 hope it helps
Answer:
Soru okunmuyor keşke fotoğrafını çekip atsaydın öyle atarsan sorunu çözerim
İYİ DERSLER
The solution for this problem is computed by through this formula, F = kQq / d²Plugging in the given values above, we can now compute for the answer.
F = 8.98755e9N·m²/C² * -(7e-6C)² / (0.03m)² = -489N, the negative sign denotes attraction.
Fibrous joint functions as a suture to tightly bind bones together so they do not move.
