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2 years ago

An object weighs 55.54 newtons. What is its mass if a gravitometer indicates that g = 9.83 m/s2?

1 answer:

8 0

   Weight = (mass) x (gravity)

Divide each side by (gravity): Mass = (weight) / (gravity) =

   (55.54 N) / (9.83 m/s²) =

   5.65 kilograms

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luda_lava [24]

Answer:

Explanation:

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2 years ago

Driving along a boring stretch of interstate in Illinois, you start experimenting using the average speed equation you learned i

astra-53 [7]

The average speed would be 33.29m/s.
The average speed equation is:

$Average speed = \frac{total distance}{total time}$

First you will need to solve for the distance you traveled in each scenario. So we can solve this by getting the product of speed and the time traveled.

Scenario 1:
Speed = 29m/s
Time = 120s
Distance = ?

Distance = (29m/s)(120s)
= 3,480m

Scenario 2
Speed = 35m/s
Time = 300s
Distance = ?

Distance = (35m/s)(300s)
= 10,500m

Now that you have the distance of both, you can solve for your average speed.

$Average speed = \frac{total distance}{total time}$
$= \frac{3,480m+10,500m}{120s+300s}$
$= \frac{13,980m}{420s}$
$= 33.29m/s$

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2 years ago

If you are six feet tall how far back from a 3 foot mirror do you have to stand in order to see yourself completely?

OverLord2011 [107]

Answer:

you would have to stand 6 ft back

Explanation:

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2 years ago

A car travels around a level, circular track that is 750m across. What coefficient of friction is required to ensure the car can

Crank

The coefficient of friction must be 0.196

Explanation:

For a car moving on a circular track, the frictional force provides the centripetal force needed to keep the car in circular motion. Therefore, we can write:

$\mu mg = m\frac{v^2}{r}$

where the term on the left is the frictional force acting between the tires of the car and the road, while the term on the right is the centripetal force. The various terms are:

$\mu$ is the coefficient of friction between the tires and the road

m is the mass of the car

$g=9.8 m/s^2$ is the acceleration of gravity

v is the speed of the car

r is the radius of the curve

In this problem,

r = 750 m is the radius

$v=85 mph \cdot \frac{1609}{3600}=38.0 m/s$ is the speed

And solving for $\mu$ , we find the coefficient of friction required to keep the car in circular motion:

$\mu = \frac{v^2}{rg}=\frac{38.0^2}{(750)(9.8)}=0.196$

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

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2 years ago

A wad of clay of mass m1 = 0.49 kg with an initial horizontal velocity v1 = 1.89 m/s hits and adheres to the massless rigid bar

notka56 [123]

Answer:

<h2>The angular velocity just after collision is given as</h2><h2> $\omega = 0.23 rad/s$ </h2><h2>At the time of collision the hinge point will exert net external force on it so linear momentum is not conserved</h2>

Explanation:

As per given figure we know that there is no external torque about hinge point on the system of given mass

So here we will have

$L_i = L_f$

now we can say

$m_1v_1\frac{L}{2} = (m_2L^2 + m_1(\frac{L}{2})^2)\omega$

so we will have

$0.49(1.89)(0.45) = (2.13(0.90)^2 + 0.49(0.45)^2)\omega$

$\omega = 0.23 rad/s$

Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass

So we can use angular momentum conservation about the hinge point

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2 years ago