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2 years ago

9

Can someone help me with both these problems?? Thx!

1 answer:

Vanyuwa [196]2 years ago

3 0

#9 is yes because 12 is double 6. 6+6=12 I don't know #10. Sorry!

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I Need help wit this.

Art [367]

Answer:

Quadrant IV

Quadrant IV (Also known as Quadrant 4) is made of negative (left) and positive (top)

7 0

2 years ago

Can you help me with #6???

AnnZ [28]

What are you asking?

6 0

3 years ago

Read 2 more answers

A, B & C form the vertices of a triangle.

kirza4 [7]

<h3>Answer: 20.3</h3>

Work Shown:

tan(angle) = opposite/adjacent

tan(B) = AC/AB

tan(67) = x/8.6

8.6*tan(67) = x

x = 8.6*tan(67)

x = 20.2603303460843 ... make sure your calculator is in degree mode

x = 20.3 .... rounding to 3 significant figures

see diagram below

6 0

2 years ago

Hey i really need help with this. thank you:))

balandron [24]

Given:

$L=2\dfrac{1}{2}$ ft and $W=3\dfrac{2}{5}$ ft.

$P=2L+2W$

To find:

The value of P.

Solution:

We have,

$P=2L+2W$

Substituting $L=2\dfrac{1}{2}$ and $W=3\dfrac{2}{5}$ , we get

$P=2\times 2\dfrac{1}{2}+2\times 3\dfrac{2}{5}$

$P=2\times \dfrac{2(2)+1}{2}+2\times \dfrac{3(5)+2}{5}$

$P=2\times \dfrac{5}{2}+2\times \dfrac{17}{5}$

$P=5+\dfrac{34}{5}$

Taking LCM, we get

$P=\dfrac{5(5)+34}{5}$

$P=\dfrac{25+34}{5}$

$P=\dfrac{59}{5}$

$P=11\dfrac{4}{5}$

Therefore, the value of P is $11\dfrac{4}{5}$ ft.

7 0

2 years ago

Find c, the hypotenuse, rounded to four decimal places, in a right triangle with b = 16 and B = 55

Fudgin [204]

Answer:

c=19.5324

Step-by-step explanation:

In given triangle ABC, we have been give values of angle B=55 degree, angle C is right angle and b=16.

Now using those values, we need to find the value of side b.

apply formula of sin

$\sin\left(B\right)=\frac{AC}{AB}$

$\sin\left(55\right)=\frac{16}{c}$

$0.819152=\frac{16}{c}$

$0.819152c=16$

$c=\frac{16}{0.819152}$

$c=19.5323944762$

Hence final answer rounded to four decimal places is c=19.5324

4 0

2 years ago