Answer:
Step-by-step explanation:
A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your
b2n+32n+3 = 2 (2n+2)22 b2n+12n+1
your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:
1. Either placing a 1 in available n places (because you can't place it at the end)
2. or by placing a zero in available n+1 places.
0 ϵ P
x ϵ P → 1x ϵ P , x1 ϵ P
x' ϵ P,x'' ϵ P → xx'x''ϵ P
Surface area is the area of all the sides added up. If you were to unfold all the areas and make it flat (2-D), area is
.
Volume would be cubed because it's 3-D
What is there to solve
be more specific
Answer:
x = 15
Step-by-step explanation:
Substitute: -4/5x + 7 = -5
Rearrange unknown terms to the left side of the equation: -4/5x = -5 - 7
Calculate the sum or difference: -4/5x = -12
Divide both sides of the equation by the coefficient of variable: x = -12 × (-5/4)
Remove the parentheses: x = 12 × 5/4
Cross out the common factor: x = 3 × 5
Calculate the product or quotient: x = 15
So the answer is: x = 15