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2 years ago

My question is that is 22.7 degrees colder than 96.5 degrees?

Mathematics

2 answers:

KiRa [710]2 years ago

4 0

Yes 22.7 degrees is colder, because it is a lower number than 96.5

Daniel [21]2 years ago

3 0

Answer:

73.8 degrees because 96.5-22.7=73.8

Step-by-step explanation:

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What is the sum of the polynomials?<br> (7x^3– 4x^2) + (2x^3 +3x)

DaniilM [7]

Answer:

sum of the polynomials is $9 x^{3} - 4 x^{2} +3x$

Step-by-step explanation:

Given polynomial is (7 x^3– 4 x^2) + (2 x^3 +3 x)

adding x^3 terms, now we get

$(7+2)x^3-4 x^2+3 x$

$9 x^{3} - 4 x^2 +3 x$

Therefore the sum of given polynomial is

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2 years ago

Solve x2 + 8x + 22 = 0 by completing the square.

Liula [17]

Answer:

Step-by-step explanation:

the solution of a squared equation is

x = (-b ± sqrt(b² - 4ac)) / (2a)

in our case

a = 1

b = 8

c = 22

x = (-8 ± sqrt(64 - 88))/2 = (-8 ± sqrt(-24))/2 =

= (-8 ± sqrt(4×-6))/2 = (-8 ± 2×sqrt(-6))/2 =

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2 years ago

A farmer has 520 feet of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one s

Setler [38]

Answer:

$310\text{ feet and }210\text{ feet}$

Step-by-step explanation:

GIVEN: A farmer has $520 \text{ feet}$ of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is $310 \text{ feet}$ .

TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.

SOLUTION:

Let the length of rectangle be $x$ and $y$

perimeter of rectangular pen $=2(x+y)=520\text{ feet}$

$x+y=260$

$y=260-x$

area of rectangular pen $=\text{length}\times\text{width}$

$=xy$

putting value of $y$

$=x(260-x)$

$=260x-x^2$

to maximize $\frac{d \text{(area)}}{dx}=0$

$260-2x=0$

$x=130\text{ feet}$

$y=390\text{ feet}$

but the dimensions must be lesser or equal to than that of barn.

therefore maximum length rectangular pen $=310\text{ feet}$

width of rectangular pen $=210\text{ feet}$

Maximum area of rectangular pen $=310\times210=65100\text{ feet}^2$

Hence maximum area of rectangular pen is $65100\text{ feet}^2$ and dimensions are $310\text{ feet and }210\text{ feet}$

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